19 of the visitors at a park were women. 90% of the remaining visitors were men and the rest were children. The number of men was 918 more than the total number of women and children. After some men left the park, 60% of the visitors that remained were men. How many men left the park?
Women |
Children |
Men |
Total |
1x5 |
8x5 |
9x5 |
|
1x4 |
9x4 |
|
5 |
4 |
36 |
45 |
|
Women and children |
Men |
Before |
9x2 = 18 u |
36x2 = 72 u |
Change |
|
- 45 u |
After
|
2x9 = 18 u |
3x9 = 27 u |
90% =
90100 =
910 Children : Men = 1 : 9
The total number of children and men at first is repeated. Make the total number of children at first the same. LCM of 8 and 10 is 40.
60% =
60100 =
35 When some men left, the total number of women and children remains unchanged. Make the total number of women and children the same. LCM of 9 and 2 is 18.
The number of men was 918 more than the total number of women and children at first.
Number of more men than the total number of women and children at first
= 72 u - 18 u
= 54 u
54 u = 918
1 u = 918 ÷ 54 = 17
Number of men who left the park
= 72 u - 27 u
= 45 u
= 45 x 17
= 765
Answer(s): 765