29 of the visitors at a zoo were men. 80% of the remaining visitors were women and the rest were children. The number of women was 352 more than the total number of men and children. After some women left the zoo, 60% of the visitors that remained were women. How many women left the zoo?
Men |
Children |
Women |
Total |
2x5 |
7x5 |
9x5 |
|
1x7 |
4x7 |
|
10 |
7 |
28 |
45 |
|
Men and children |
Women |
Before |
17x2 = 34 u |
28x2 = 56 u |
Change |
|
- 5 u |
After
|
2x17 = 34 u |
3x17 = 51 u |
80% =
80100 =
45 Children : Women = 1 : 4
The total number of children and women at first is repeated. Make the total number of children at first the same. LCM of 7 and 5 is 35.
60% =
60100 =
35 When some women left, the total number of men and children remains unchanged. Make the total number of men and children the same. LCM of 17 and 2 is 34.
The number of women was 352 more than the total number of men and children at first.
Number of more women than the total number of men and children at first
= 56 u - 34 u
= 22 u
22 u = 352
1 u = 352 ÷ 22 = 16
Number of women who left the zoo
= 56 u - 51 u
= 5 u
= 5 x 16
= 80
Answer(s): 80