Albert, Oscar and Japheth sold some markers. Japheth sold 40% of the total number of markers sold by Oscar and Albert. Albert sold 10% of the total number of markers sold by Oscar and Japheth. Albert sold 369 less markers than Oscar. Find the total number of markers sold by all the boys.
| Albert |
Oscar |
Japheth |
Total |
| 5x11 |
2x11 |
7x11 |
| 1x7 |
10x7 |
11x7 |
| 7 u |
48 u |
22 u |
77 u |
40% =
40100 =
25 10% =
10100 =
110 The total number of markers is repeated. Make the total number of markers the same. LCM of 7 and 11 is 77.
Number of less markers that Albert sold than Oscar
= 48 u - 7 u
= 41 u
41 u = 369
1 u = 369 ÷ 41 = 9
Total number of markers sold
= 77 u
= 77 x 9
= 693
Answer(s): 693
