Cole, Pierre and Ivan shared a sum of money. Cole and Pierre received 90% of the total amount of money. Pierre and Ivan received 40% of the total amount of money. Given that Pierre received $48 less than Cole, how much was the sum of money that was shared by Pierre and Ivan?
| Cole |
Pierre |
Ivan |
Total |
| 9x1 |
1x1 |
10x1 |
| 3x2 |
2x2 |
5x2 |
| 6 u |
3 u |
1 u |
10 u |
90% =
90100 =
910 40% =
40100 =
25 The total amount of money that Cole, Pierre and Ivan shared is repeated. Make the total amount of money the same. LCM of 10 and 5 is 10.
Amount that Pierre received less than Cole
= 6 u - 3 u
= 3 u
3 u = 48
1 u = 48 ÷ 3 = 16
Amount that Pierre and Ivan shared
= 3 u + 1 u
= 4 u
= 4 x 16
= $64
Answer(s): $64
