Sam, Tom and Xavier shared a sum of money. Sam and Tom received 90% of the total amount of money. Tom and Xavier received 50% of the total amount of money. Given that Sam received $48 more than Xavier, how much was the sum of money that was shared by Sam and Xavier?
| Sam |
Tom |
Xavier |
Total |
| 9x1 |
1x1 |
10x1 |
| 1x5 |
1x5 |
2x5 |
| 5 u |
4 u |
1 u |
10 u |
90% =
90100 =
910 50% =
50100 =
12 The total amount of money that Sam, Tom and Xavier shared is repeated. Make the total amount of money the same. LCM of 10 and 2 is 10.
Amount that Sam received more than Xavier
= 5 u - 1 u
= 4 u
4 u = 48
1 u = 48 ÷ 4 = 12
Amount that Sam and Xavier shared
= 5 u + 1 u
= 6 u
= 6 x 12
= $72
Answer(s): $72
