Brandon, Dylan and Carl shared a sum of money. Brandon and Dylan received 80% of the total amount of money. Dylan and Carl received 50% of the total amount of money. Given that Brandon received $21 more than Carl, how much was the sum of money that was shared by Brandon and Carl?
Brandon |
Dylan |
Carl |
Total |
4x2 |
1x2 |
5x2 |
1x5 |
1x5 |
2x5 |
5 u |
3 u |
2 u |
10 u |
80% =
80100 =
45 50% =
50100 =
12 The total amount of money that Brandon, Dylan and Carl shared is repeated. Make the total amount of money the same. LCM of 5 and 2 is 10.
Amount that Brandon received more than Carl
= 5 u - 2 u
= 3 u
3 u = 21
1 u = 21 ÷ 3 = 7
Amount that Brandon and Carl shared
= 5 u + 2 u
= 7 u
= 7 x 7
= $49
Answer(s): $49