Jean, Tiffany and Gem had 900 coins. Tiffany won some of the coins from Jean and as a result, Tiffany's coins increased by 25%. Gem then won some coins from Tiffany and Gem's coins increased by 75%. Finally, Gem lost some of her coins to Jean and Jean's coins increased by 20%. In the end, they realised that they each had an equal number of coins. How many percent less did Jean have in the end than what she had at first? Correct your answer to 1 decimal place.

Jean	Tiffany	Gem
900
	4 u
- 1 u	+ 1 u
	5 u
		4 p
	- 3 p	+ 3 p
		7 p
5 boxes
+ 1 box		- 1 box
6 boxes
1 group	1 group	1 group

25% = ²⁵₁₀₀ = ¹₄
75% = ⁷⁵₁₀₀ = ³₄
20% = ²⁰₁₀₀ = ¹₅

Working backwards.

3 groups = 900

1 group = 900 ÷ 3 = 300

1 group = 6 boxes
6 boxes = 300

1 box = 300 ÷ 6 = 50

1 group + 1 box = 7 p
300 + 50 = 7 p
7 p = 350

1 p = 350 ÷ 7 = 50

3 p = 3 x 50 = 150

1 group + 3 p = 5 u
300 + 150 = 5 u
5 u = 450

1 u = 450 ÷ 5 = 90

Number of coins that Jean had at first
= 5 boxes + 1 u
= (5 x 50) + 90
= 250 + 90
= 340

Percent that Jean had less in the end than at first
= ^{340 - 300}₃₄₀ x 100%
≈ 11.8%

Answer(s): 11.8%