Zara, Penelope and Roshel had 1116 coins. Penelope won some of the coins from Zara and as a result, Penelope's coins increased by 50%. Roshel then won some coins from Penelope and Roshel's coins increased by 75%. Finally, Roshel lost some of her coins to Zara and Zara's coins increased by 20%. In the end, they realised that they each had an equal number of coins. How many percent less did Zara have in the end than what she had at first? Correct your answer to 1 decimal place.

Zara	Penelope	Roshel
1116
	2 u
- 1 u	+ 1 u
	3 u
		4 p
	- 3 p	+ 3 p
		7 p
5 boxes
+ 1 box		- 1 box
6 boxes
1 group	1 group	1 group

50% = ⁵⁰₁₀₀ = ¹₂
75% = ⁷⁵₁₀₀ = ³₄
20% = ²⁰₁₀₀ = ¹₅

Working backwards.

3 groups = 1116

1 group = 1116 ÷ 3 = 372

1 group = 6 boxes
6 boxes = 372

1 box = 372 ÷ 6 = 62

1 group + 1 box = 7 p
372 + 62 = 7 p
7 p = 434

1 p = 434 ÷ 7 = 62

3 p = 3 x 62 = 186

1 group + 3 p = 3 u
372 + 186 = 3 u
3 u = 558

1 u = 558 ÷ 3 = 186

Number of coins that Zara had at first
= 5 boxes + 1 u
= (5 x 62) + 186
= 310 + 186
= 496

Percent that Zara had less in the end than at first
= ^{496 - 372}₄₉₆ x 100%
≈ 25.0%

Answer(s): 25.0%