Elyse, Jaslyn and Shiyun had 720 coins. Jaslyn won some of the coins from Elyse and as a result, Jaslyn's coins increased by 50%. Shiyun then won some coins from Jaslyn and Shiyun's coins increased by 60%. Finally, Shiyun lost some of her coins to Elyse and Elyse's coins increased by 20%. In the end, they realised that they each had an equal number of coins. How many percent less did Elyse have in the end than what she had at first? Correct your answer to 1 decimal place.

Elyse	Jaslyn	Shiyun
720
	2 u
- 1 u	+ 1 u
	3 u
		5 p
	- 3 p	+ 3 p
		8 p
5 boxes
+ 1 box		- 1 box
6 boxes
1 group	1 group	1 group

50% = ⁵⁰₁₀₀ = ¹₂
60% = ⁶⁰₁₀₀ = ³₅
20% = ²⁰₁₀₀ = ¹₅

Working backwards.

3 groups = 720

1 group = 720 ÷ 3 = 240

1 group = 6 boxes
6 boxes = 240

1 box = 240 ÷ 6 = 40

1 group + 1 box = 8 p
240 + 40 = 8 p
8 p = 280

1 p = 280 ÷ 8 = 35

3 p = 3 x 35 = 105

1 group + 3 p = 3 u
240 + 105 = 3 u
3 u = 345

1 u = 345 ÷ 3 = 115

Number of coins that Elyse had at first
= 5 boxes + 1 u
= (5 x 40) + 115
= 200 + 115
= 315

Percent that Elyse had less in the end than at first
= ^{315 - 240}₃₁₅ x 100%
≈ 23.8%

Answer(s): 23.8%