Natalie, Opal and Shannon had 810 stamps. Opal won some of the stamps from Natalie and as a result, Opal's stamps increased by 50%. Shannon then won some stamps from Opal and Shannon's stamps increased by 75%. Finally, Shannon lost some of her stamps to Natalie and Natalie's stamps increased by 20%. In the end, they realised that they each had an equal number of stamps. How many percent less did Natalie have in the end than what she had at first? Correct your answer to 1 decimal place.
Natalie |
Opal |
Shannon |
810 |
|
2 u |
|
- 1 u |
+ 1 u |
|
|
3 u |
|
|
|
4 p |
|
- 3 p |
+ 3 p |
|
|
7 p |
5 boxes |
|
|
+ 1 box |
|
- 1 box |
6 boxes |
|
|
1 group |
1 group |
1 group |
50% =
50100 =
1275% =
75100 =
3420% =
20100 =
15Working backwards.
3 groups = 810
1 group = 810 ÷ 3 = 270
1 group = 6 boxes
6 boxes = 270
1 box = 270 ÷ 6 = 45
1 group + 1 box = 7 p
270 + 45 = 7 p
7 p = 315
1 p = 315 ÷ 7 = 45
3 p = 3 x 45 = 135
1 group + 3 p = 3 u
270 + 135 = 3 u
3 u = 405
1 u = 405 ÷ 3 = 135
Number of stamps that Natalie had at first
= 5 boxes + 1 u
= (5 x 45) + 135
= 225 + 135
= 360
Percent that Natalie had less in the end than at first
=
360 - 270360 x 100%
≈ 25.0%
Answer(s): 25.0%