Jean, Nora and Lynn had 630 coins. Nora won some of the coins from Jean and as a result, Nora's coins increased by 25%. Lynn then won some coins from Nora and Lynn's coins increased by 40%. Finally, Lynn lost some of her coins to Jean and Jean's coins increased by 20%. In the end, they realised that they each had an equal number of coins. How many percent less did Jean have in the end than what she had at first? Correct your answer to 1 decimal place.

Jean	Nora	Lynn
630
	4 u
- 1 u	+ 1 u
	5 u
		5 p
	- 2 p	+ 2 p
		7 p
5 boxes
+ 1 box		- 1 box
6 boxes
1 group	1 group	1 group

25% = ²⁵₁₀₀ = ¹₄
40% = ⁴⁰₁₀₀ = ²₅
20% = ²⁰₁₀₀ = ¹₅

Working backwards.

3 groups = 630

1 group = 630 ÷ 3 = 210

1 group = 6 boxes
6 boxes = 210

1 box = 210 ÷ 6 = 35

1 group + 1 box = 7 p
210 + 35 = 7 p
7 p = 245

1 p = 245 ÷ 7 = 35

2 p = 2 x 35 = 70

1 group + 2 p = 5 u
210 + 70 = 5 u
5 u = 280

1 u = 280 ÷ 5 = 56

Number of coins that Jean had at first
= 5 boxes + 1 u
= (5 x 35) + 56
= 175 + 56
= 231

Percent that Jean had less in the end than at first
= ^{231 - 210}₂₃₁ x 100%
≈ 9.1%

Answer(s): 9.1%