Vanessa, Hazel and Jen had 1170 coins. Hazel won some of the coins from Vanessa and as a result, Hazel's coins increased by 25%. Jen then won some coins from Hazel and Jen's coins increased by 75%. Finally, Jen lost some of her coins to Vanessa and Vanessa's coins increased by 20%. In the end, they realised that they each had an equal number of coins. How many percent less did Vanessa have in the end than what she had at first? Correct your answer to 1 decimal place.

Vanessa	Hazel	Jen
1170
	4 u
- 1 u	+ 1 u
	5 u
		4 p
	- 3 p	+ 3 p
		7 p
5 boxes
+ 1 box		- 1 box
6 boxes
1 group	1 group	1 group

25% = ²⁵₁₀₀ = ¹₄
75% = ⁷⁵₁₀₀ = ³₄
20% = ²⁰₁₀₀ = ¹₅

Working backwards.

3 groups = 1170

1 group = 1170 ÷ 3 = 390

1 group = 6 boxes
6 boxes = 390

1 box = 390 ÷ 6 = 65

1 group + 1 box = 7 p
390 + 65 = 7 p
7 p = 455

1 p = 455 ÷ 7 = 65

3 p = 3 x 65 = 195

1 group + 3 p = 5 u
390 + 195 = 5 u
5 u = 585

1 u = 585 ÷ 5 = 117

Number of coins that Vanessa had at first
= 5 boxes + 1 u
= (5 x 65) + 117
= 325 + 117
= 442

Percent that Vanessa had less in the end than at first
= ^{442 - 390}₄₄₂ x 100%
≈ 11.8%

Answer(s): 11.8%