Kylie, Tina and Sabrina had 1098 stamps. Tina won some of the stamps from Kylie and as a result, Tina's stamps increased by 50%. Sabrina then won some stamps from Tina and Sabrina's stamps increased by 75%. Finally, Sabrina lost some of her stamps to Kylie and Kylie's stamps increased by 20%. In the end, they realised that they each had an equal number of stamps. How many percent less did Kylie have in the end than what she had at first? Correct your answer to 1 decimal place.
Kylie |
Tina |
Sabrina |
1098 |
|
2 u |
|
- 1 u |
+ 1 u |
|
|
3 u |
|
|
|
4 p |
|
- 3 p |
+ 3 p |
|
|
7 p |
5 boxes |
|
|
+ 1 box |
|
- 1 box |
6 boxes |
|
|
1 group |
1 group |
1 group |
50% =
50100 =
1275% =
75100 =
3420% =
20100 =
15Working backwards.
3 groups = 1098
1 group = 1098 ÷ 3 = 366
1 group = 6 boxes
6 boxes = 366
1 box = 366 ÷ 6 = 61
1 group + 1 box = 7 p
366 + 61 = 7 p
7 p = 427
1 p = 427 ÷ 7 = 61
3 p = 3 x 61 = 183
1 group + 3 p = 3 u
366 + 183 = 3 u
3 u = 549
1 u = 549 ÷ 3 = 183
Number of stamps that Kylie had at first
= 5 boxes + 1 u
= (5 x 61) + 183
= 305 + 183
= 488
Percent that Kylie had less in the end than at first
=
488 - 366488 x 100%
≈ 25.0%
Answer(s): 25.0%