Hazel, Mary and Jaslyn had 756 cards. Mary won some of the cards from Hazel and as a result, Mary's cards increased by 25%. Jaslyn then won some cards from Mary and Jaslyn's cards increased by 50%. Finally, Jaslyn lost some of her cards to Hazel and Hazel's cards increased by 20%. In the end, they realised that they each had an equal number of cards. How many percent less did Hazel have in the end than what she had at first? Correct your answer to 1 decimal place.
Hazel |
Mary |
Jaslyn |
756 |
|
4 u |
|
- 1 u |
+ 1 u |
|
|
5 u |
|
|
|
2 p |
|
- 1 p |
+ 1 p |
|
|
3 p |
5 boxes |
|
|
+ 1 box |
|
- 1 box |
6 boxes |
|
|
1 group |
1 group |
1 group |
25% =
25100 =
1450% =
50100 =
1220% =
20100 =
15Working backwards.
3 groups = 756
1 group = 756 ÷ 3 = 252
1 group = 6 boxes
6 boxes = 252
1 box = 252 ÷ 6 = 42
1 group + 1 box = 3 p
252 + 42 = 3 p
3 p = 294
1 p = 294 ÷ 3 = 98
1 p = 1 x 98 = 98
1 group + 1 p = 5 u
252 + 98 = 5 u
5 u = 350
1 u = 350 ÷ 5 = 70
Number of cards that Hazel had at first
= 5 boxes + 1 u
= (5 x 42) + 70
= 210 + 70
= 280
Percent that Hazel had less in the end than at first
=
280 - 252280 x 100%
≈ 10.0%
Answer(s): 10.0%