Jean, Vanessa and Raeann had 1350 stickers. Vanessa won some of the stickers from Jean and as a result, Vanessa's stickers increased by 50%. Raeann then won some stickers from Vanessa and Raeann's stickers increased by 80%. Finally, Raeann lost some of her stickers to Jean and Jean's stickers increased by 25%. In the end, they realised that they each had an equal number of stickers. How many percent less did Jean have in the end than what she had at first? Correct your answer to 1 decimal place.

Jean	Vanessa	Raeann
1350
	2 u
- 1 u	+ 1 u
	3 u
		5 p
	- 4 p	+ 4 p
		9 p
4 boxes
+ 1 box		- 1 box
5 boxes
1 group	1 group	1 group

50% = ⁵⁰₁₀₀ = ¹₂
80% = ⁸⁰₁₀₀ = ⁴₅
25% = ²⁵₁₀₀ = ¹₄

Working backwards.

3 groups = 1350

1 group = 1350 ÷ 3 = 450

1 group = 5 boxes
5 boxes = 450

1 box = 450 ÷ 5 = 90

1 group + 1 box = 9 p
450 + 90 = 9 p
9 p = 540

1 p = 540 ÷ 9 = 60

4 p = 4 x 60 = 240

1 group + 4 p = 3 u
450 + 240 = 3 u
3 u = 690

1 u = 690 ÷ 3 = 230

Number of stickers that Jean had at first
= 4 boxes + 1 u
= (4 x 90) + 230
= 360 + 230
= 590

Percent that Jean had less in the end than at first
= ^{590 - 450}₅₉₀ x 100%
≈ 23.7%

Answer(s): 23.7%