Victoria, Cindy and Yoko had 1170 beads. Cindy won some of the beads from Victoria and as a result, Cindy's beads increased by 20%. Yoko then won some beads from Cindy and Yoko's beads increased by 30%. Finally, Yoko lost some of her beads to Victoria and Victoria's beads increased by 25%. In the end, they realised that they each had an equal number of beads. How many percent less did Victoria have in the end than what she had at first? Correct your answer to 1 decimal place.
Victoria |
Cindy |
Yoko |
1170 |
|
5 u |
|
- 1 u |
+ 1 u |
|
|
6 u |
|
|
|
10 p |
|
- 3 p |
+ 3 p |
|
|
13 p |
4 boxes |
|
|
+ 1 box |
|
- 1 box |
5 boxes |
|
|
1 group |
1 group |
1 group |
20% =
20100 =
1530% =
30100 =
31025% =
25100 =
14Working backwards.
3 groups = 1170
1 group = 1170 ÷ 3 = 390
1 group = 5 boxes
5 boxes = 390
1 box = 390 ÷ 5 = 78
1 group + 1 box = 13 p
390 + 78 = 13 p
13 p = 468
1 p = 468 ÷ 13 = 36
3 p = 3 x 36 = 108
1 group + 3 p = 6 u
390 + 108 = 6 u
6 u = 498
1 u = 498 ÷ 6 = 83
Number of beads that Victoria had at first
= 4 boxes + 1 u
= (4 x 78) + 83
= 312 + 83
= 395
Percent that Victoria had less in the end than at first
=
395 - 390395 x 100%
≈ 1.3%
Answer(s): 1.3%