Pamela, Jaslyn and Kylie had 990 stickers. Jaslyn won some of the stickers from Pamela and as a result, Jaslyn's stickers increased by 25%. Kylie then won some stickers from Jaslyn and Kylie's stickers increased by 40%. Finally, Kylie lost some of her stickers to Pamela and Pamela's stickers increased by 20%. In the end, they realised that they each had an equal number of stickers. How many percent less did Pamela have in the end than what she had at first? Correct your answer to 1 decimal place.

Pamela	Jaslyn	Kylie
990
	4 u
- 1 u	+ 1 u
	5 u
		5 p
	- 2 p	+ 2 p
		7 p
5 boxes
+ 1 box		- 1 box
6 boxes
1 group	1 group	1 group

25% = ²⁵₁₀₀ = ¹₄
40% = ⁴⁰₁₀₀ = ²₅
20% = ²⁰₁₀₀ = ¹₅

Working backwards.

3 groups = 990

1 group = 990 ÷ 3 = 330

1 group = 6 boxes
6 boxes = 330

1 box = 330 ÷ 6 = 55

1 group + 1 box = 7 p
330 + 55 = 7 p
7 p = 385

1 p = 385 ÷ 7 = 55

2 p = 2 x 55 = 110

1 group + 2 p = 5 u
330 + 110 = 5 u
5 u = 440

1 u = 440 ÷ 5 = 88

Number of stickers that Pamela had at first
= 5 boxes + 1 u
= (5 x 55) + 88
= 275 + 88
= 363

Percent that Pamela had less in the end than at first
= ^{363 - 330}₃₆₃ x 100%
≈ 9.1%

Answer(s): 9.1%