Jade, Betty and Kathy had 1134 coins. Betty won some of the coins from Jade and as a result, Betty's coins increased by 50%. Kathy then won some coins from Betty and Kathy's coins increased by 40%. Finally, Kathy lost some of her coins to Jade and Jade's coins increased by 20%. In the end, they realised that they each had an equal number of coins. How many percent less did Jade have in the end than what she had at first? Correct your answer to 1 decimal place.

Jade	Betty	Kathy
1134
	2 u
- 1 u	+ 1 u
	3 u
		5 p
	- 2 p	+ 2 p
		7 p
5 boxes
+ 1 box		- 1 box
6 boxes
1 group	1 group	1 group

50% = ⁵⁰₁₀₀ = ¹₂
40% = ⁴⁰₁₀₀ = ²₅
20% = ²⁰₁₀₀ = ¹₅

Working backwards.

3 groups = 1134

1 group = 1134 ÷ 3 = 378

1 group = 6 boxes
6 boxes = 378

1 box = 378 ÷ 6 = 63

1 group + 1 box = 7 p
378 + 63 = 7 p
7 p = 441

1 p = 441 ÷ 7 = 63

2 p = 2 x 63 = 126

1 group + 2 p = 3 u
378 + 126 = 3 u
3 u = 504

1 u = 504 ÷ 3 = 168

Number of coins that Jade had at first
= 5 boxes + 1 u
= (5 x 63) + 168
= 315 + 168
= 483

Percent that Jade had less in the end than at first
= ^{483 - 378}₄₈₃ x 100%
≈ 21.7%

Answer(s): 21.7%