Xandra, Kimberly and Victoria had 1188 coins. Kimberly won some of the coins from Xandra and as a result, Kimberly's coins increased by 50%. Victoria then won some coins from Kimberly and Victoria's coins increased by 75%. Finally, Victoria lost some of her coins to Xandra and Xandra's coins increased by 20%. In the end, they realised that they each had an equal number of coins. How many percent less did Xandra have in the end than what she had at first? Correct your answer to 1 decimal place.

Xandra	Kimberly	Victoria
1188
	2 u
- 1 u	+ 1 u
	3 u
		4 p
	- 3 p	+ 3 p
		7 p
5 boxes
+ 1 box		- 1 box
6 boxes
1 group	1 group	1 group

50% = ⁵⁰₁₀₀ = ¹₂
75% = ⁷⁵₁₀₀ = ³₄
20% = ²⁰₁₀₀ = ¹₅

Working backwards.

3 groups = 1188

1 group = 1188 ÷ 3 = 396

1 group = 6 boxes
6 boxes = 396

1 box = 396 ÷ 6 = 66

1 group + 1 box = 7 p
396 + 66 = 7 p
7 p = 462

1 p = 462 ÷ 7 = 66

3 p = 3 x 66 = 198

1 group + 3 p = 3 u
396 + 198 = 3 u
3 u = 594

1 u = 594 ÷ 3 = 198

Number of coins that Xandra had at first
= 5 boxes + 1 u
= (5 x 66) + 198
= 330 + 198
= 528

Percent that Xandra had less in the end than at first
= ^{528 - 396}₅₂₈ x 100%
≈ 25.0%

Answer(s): 25.0%