Hazel, Roshel and Jen had 1170 erasers. Roshel won some of the erasers from Hazel and as a result, Roshel's erasers increased by 25%. Jen then won some erasers from Roshel and Jen's erasers increased by 30%. Finally, Jen lost some of her erasers to Hazel and Hazel's erasers increased by 20%. In the end, they realised that they each had an equal number of erasers. How many percent less did Hazel have in the end than what she had at first? Correct your answer to 1 decimal place.

Hazel	Roshel	Jen
1170
	4 u
- 1 u	+ 1 u
	5 u
		10 p
	- 3 p	+ 3 p
		13 p
5 boxes
+ 1 box		- 1 box
6 boxes
1 group	1 group	1 group

25% = ²⁵₁₀₀ = ¹₄
30% = ³⁰₁₀₀ = ³₁₀
20% = ²⁰₁₀₀ = ¹₅

Working backwards.

3 groups = 1170

1 group = 1170 ÷ 3 = 390

1 group = 6 boxes
6 boxes = 390

1 box = 390 ÷ 6 = 65

1 group + 1 box = 13 p
390 + 65 = 13 p
13 p = 455

1 p = 455 ÷ 13 = 35

3 p = 3 x 35 = 105

1 group + 3 p = 5 u
390 + 105 = 5 u
5 u = 495

1 u = 495 ÷ 5 = 99

Number of erasers that Hazel had at first
= 5 boxes + 1 u
= (5 x 65) + 99
= 325 + 99
= 424

Percent that Hazel had less in the end than at first
= ^{424 - 390}₄₂₄ x 100%
≈ 8%

Answer(s): 8%