Natalie, Jean and Jen had 810 stickers. Jean won some of the stickers from Natalie and as a result, Jean's stickers increased by 50%. Jen then won some stickers from Jean and Jen's stickers increased by 80%. Finally, Jen lost some of her stickers to Natalie and Natalie's stickers increased by 25%. In the end, they realised that they each had an equal number of stickers. How many percent less did Natalie have in the end than what she had at first? Correct your answer to 1 decimal place.

Natalie	Jean	Jen
810
	2 u
- 1 u	+ 1 u
	3 u
		5 p
	- 4 p	+ 4 p
		9 p
4 boxes
+ 1 box		- 1 box
5 boxes
1 group	1 group	1 group

50% = ⁵⁰₁₀₀ = ¹₂
80% = ⁸⁰₁₀₀ = ⁴₅
25% = ²⁵₁₀₀ = ¹₄

Working backwards.

3 groups = 810

1 group = 810 ÷ 3 = 270

1 group = 5 boxes
5 boxes = 270

1 box = 270 ÷ 5 = 54

1 group + 1 box = 9 p
270 + 54 = 9 p
9 p = 324

1 p = 324 ÷ 9 = 36

4 p = 4 x 36 = 144

1 group + 4 p = 3 u
270 + 144 = 3 u
3 u = 414

1 u = 414 ÷ 3 = 138

Number of stickers that Natalie had at first
= 4 boxes + 1 u
= (4 x 54) + 138
= 216 + 138
= 354

Percent that Natalie had less in the end than at first
= ^{354 - 270}₃₅₄ x 100%
≈ 23.7%

Answer(s): 23.7%