Jane, Xylia and Opal had 1260 erasers. Xylia won some of the erasers from Jane and as a result, Xylia's erasers increased by 50%. Opal then won some erasers from Xylia and Opal's erasers increased by 60%. Finally, Opal lost some of her erasers to Jane and Jane's erasers increased by 25%. In the end, they realised that they each had an equal number of erasers. How many percent less did Jane have in the end than what she had at first? Correct your answer to 1 decimal place.

Jane	Xylia	Opal
1260
	2 u
- 1 u	+ 1 u
	3 u
		5 p
	- 3 p	+ 3 p
		8 p
4 boxes
+ 1 box		- 1 box
5 boxes
1 group	1 group	1 group

50% = ⁵⁰₁₀₀ = ¹₂
60% = ⁶⁰₁₀₀ = ³₅
25% = ²⁵₁₀₀ = ¹₄

Working backwards.

3 groups = 1260

1 group = 1260 ÷ 3 = 420

1 group = 5 boxes
5 boxes = 420

1 box = 420 ÷ 5 = 84

1 group + 1 box = 8 p
420 + 84 = 8 p
8 p = 504

1 p = 504 ÷ 8 = 63

3 p = 3 x 63 = 189

1 group + 3 p = 3 u
420 + 189 = 3 u
3 u = 609

1 u = 609 ÷ 3 = 203

Number of erasers that Jane had at first
= 4 boxes + 1 u
= (4 x 84) + 203
= 336 + 203
= 539

Percent that Jane had less in the end than at first
= ^{539 - 420}₅₃₉ x 100%
≈ 22.1%

Answer(s): 22.1%