At the night market, there were 60% as many girls as boys and 10% more adults than girls. Given that there were 21 more adults than girls at the night market, how many children were there altogether?
| Girls |
Boys |
Adults |
| 3x10 |
5x10 |
|
| 10x3 |
|
11x3 |
| 30 u |
50 u |
33 u |
60% =
60100 =
35Girls : Boys = 3 : 5
100% + 10% = 110%
110% =
110100 =
1110 Girls : Adults = 10 : 11
The number of girls is repeated. Make the number of girls the same. LCM of 3 and 10 is 30.
Number of more adults than girls
= 33 u - 30 u
= 3 u
3 u = 21
1 u = 21 ÷ 3 = 7
Number of children
= 30 u + 50 u
= 80 u
= 80 x 7
= 560
Answer(s): 560
