At the bowling alley, there were 60% as many boys as girls and 40% more adults than boys. Given that there were 30 more adults than boys at the bowling alley, how many children were there altogether?
| Boys |
Girls |
Adults |
| 3x5 |
5x5 |
|
| 5x3 |
|
7x3 |
| 15 u |
25 u |
21 u |
60% =
60100 =
35Boys : Girls = 3 : 5
100% + 40% = 140%
140% =
140100 =
75 Boys : Adults = 5 : 7
The number of boys is repeated. Make the number of boys the same. LCM of 3 and 5 is 15.
Number of more adults than boys
= 21 u - 15 u
= 6 u
6 u = 30
1 u = 30 ÷ 6 = 5
Number of children
= 15 u + 25 u
= 40 u
= 40 x 5
= 200
Answer(s): 200
