At the bowling alley, there were 60% as many men as women and 10% more children than men. Given that there were 18 less men than children at the bowling alley, how many adults were there altogether?
| Men |
Women |
Children |
| 3x10 |
5x10 |
|
| 10x3 |
|
11x3 |
| 30 u |
50 u |
33 u |
60% =
60100 =
35Men : Women = 3 : 5
100% + 10% = 110%
110% =
110100 =
1110 Men : Children = 10 : 11
The number of men is repeated. Make the number of men the same. LCM of 3 and 10 is 30.
Number of less men than children
= 33 u - 30 u
= 3 u
3 u = 18
1 u = 18 ÷ 3 = 6
Number of adults
= 30 u + 50 u
= 80 u
= 80 x 6
= 480
Answer(s): 480
