At the bowling alley, there were 40% as many boys as girls and 20% more adults than boys. Given that there were 24 more adults than boys at the bowling alley, how many children were there altogether?
| Boys |
Girls |
Adults |
| 2x5 |
5x5 |
|
| 5x2 |
|
6x2 |
| 10 u |
25 u |
12 u |
40% =
40100 =
25Boys : Girls = 2 : 5
100% + 20% = 120%
120% =
120100 =
65 Boys : Adults = 5 : 6
The number of boys is repeated. Make the number of boys the same. LCM of 2 and 5 is 10.
Number of more adults than boys
= 12 u - 10 u
= 2 u
2 u = 24
1 u = 24 ÷ 2 = 12
Number of children
= 10 u + 25 u
= 35 u
= 35 x 12
= 420
Answer(s): 420
