At the fair, there were 40% as many men as women and 20% more children than men. Given that there were 12 more children than men at the fair, how many adults were there altogether?
Men |
Women |
Children |
2x5 |
5x5 |
|
5x2 |
|
6x2 |
10 u |
25 u |
12 u |
40% =
40100 =
25Men : Women = 2 : 5
100% + 20% = 120%
120% =
120100 =
65 Men : Children = 5 : 6
The number of men is repeated. Make the number of men the same. LCM of 2 and 5 is 10.
Number of more children than men
= 12 u - 10 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of adults
= 10 u + 25 u
= 35 u
= 35 x 6
= 210
Answer(s): 210