At the bowling alley, there were 60% as many boys as girls and 20% more adults than boys. Given that there were 36 more adults than boys at the bowling alley, how many children were there altogether?
Boys |
Girls |
Adults |
3x5 |
5x5 |
|
5x3 |
|
6x3 |
15 u |
25 u |
18 u |
60% =
60100 =
35Boys : Girls = 3 : 5
100% + 20% = 120%
120% =
120100 =
65 Boys : Adults = 5 : 6
The number of boys is repeated. Make the number of boys the same. LCM of 3 and 5 is 15.
Number of more adults than boys
= 18 u - 15 u
= 3 u
3 u = 36
1 u = 36 ÷ 3 = 12
Number of children
= 15 u + 25 u
= 40 u
= 40 x 12
= 480
Answer(s): 480