At the fair, there were 60% as many men as women and 20% more children than men. Given that there were 33 less men than children at the fair, how many adults were there altogether?
| Men |
Women |
Children |
| 3x5 |
5x5 |
|
| 5x3 |
|
6x3 |
| 15 u |
25 u |
18 u |
60% =
60100 =
35Men : Women = 3 : 5
100% + 20% = 120%
120% =
120100 =
65 Men : Children = 5 : 6
The number of men is repeated. Make the number of men the same. LCM of 3 and 5 is 15.
Number of less men than children
= 18 u - 15 u
= 3 u
3 u = 33
1 u = 33 ÷ 3 = 11
Number of adults
= 15 u + 25 u
= 40 u
= 40 x 11
= 440
Answer(s): 440
