At the fair, there were 60% as many men as women and 40% more children than men. Given that there were 54 more children than men at the fair, how many adults were there altogether?
Men |
Women |
Children |
3x5 |
5x5 |
|
5x3 |
|
7x3 |
15 u |
25 u |
21 u |
60% =
60100 =
35Men : Women = 3 : 5
100% + 40% = 140%
140% =
140100 =
75 Men : Children = 5 : 7
The number of men is repeated. Make the number of men the same. LCM of 3 and 5 is 15.
Number of more children than men
= 21 u - 15 u
= 6 u
6 u = 54
1 u = 54 ÷ 6 = 9
Number of adults
= 15 u + 25 u
= 40 u
= 40 x 9
= 360
Answer(s): 360