At the bowling alley, there were 60% as many men as women and 30% more children than men. Given that there were 63 more children than men at the bowling alley, how many adults were there altogether?
| Men |
Women |
Children |
| 3x10 |
5x10 |
|
| 10x3 |
|
13x3 |
| 30 u |
50 u |
39 u |
60% =
60100 =
35Men : Women = 3 : 5
100% + 30% = 130%
130% =
130100 =
1310 Men : Children = 10 : 13
The number of men is repeated. Make the number of men the same. LCM of 3 and 10 is 30.
Number of more children than men
= 39 u - 30 u
= 9 u
9 u = 63
1 u = 63 ÷ 9 = 7
Number of adults
= 30 u + 50 u
= 80 u
= 80 x 7
= 560
Answer(s): 560
