At the bowling alley, there were 75% as many women as men and 40% more children than women. Given that there were 36 more children than women at the bowling alley, how many adults were there altogether?
| Women |
Men |
Children |
| 3x5 |
4x5 |
|
| 5x3 |
|
7x3 |
| 15 u |
20 u |
21 u |
75% =
75100 =
34Women : Men = 3 : 4
100% + 40% = 140%
140% =
140100 =
75 Women : Children = 5 : 7
The number of women is repeated. Make the number of women the same. LCM of 3 and 5 is 15.
Number of more children than women
= 21 u - 15 u
= 6 u
6 u = 36
1 u = 36 ÷ 6 = 6
Number of adults
= 15 u + 20 u
= 35 u
= 35 x 6
= 210
Answer(s): 210
