There were some chikoos in 3 baskets, V, W and X. 25% of the number of chikoos in Basket V was equal to 10% of the number of chikoos in Basket W. The number of chikoos in Basket X was 60% of the total number of chikoos. After Flynn removed 25% of the chikoos in Basket X, there were 230 more chikoos in Basket X than in Basket W. In the end, how many chikoos should be transferred from Basket W to Basket X so that the number of chikoos in Basket V would be the same as Basket W?

Basket V	Basket W	Basket X
2x2	5x2
2x7		3x7
4 u	10 u	21 u

	Basket V	Basket W	Basket X
Before	4 u	10 u	21 u
Change			- 5.25 u
After	4 u	10 u	15.75 u

25% = ²⁵₁₀₀ = ¹₄

10% = ¹⁰₁₀₀ = ¹₁₀

¹₄ Basket V = ¹₁₀ Basket W

Basket V : Basket W
4 : 10
2 : 5

60% = ⁶⁰₁₀₀ = ³₅

The total number of chikoos in Basket V and Basket W is the combined repeated identity.  Make the total number of chikoos in Box V and Basket W the same.  LCM of 7 and 2 = 14

Number of chikoos removed from Basket X
= ²⁵₁₀₀ x 21 u
= 5.25 u

Number of chikoos left in Basket X
= 21 u - 5.25 u
= 15.75 u

Number of more chikoos in Basket X than Basket W
= 15.75 u - 10 u
= 5.75 u

5.75 u = 230

1 u = 230 ÷ 5.75 = 40

	Basket V	Basket W	Basket X
Before	4 u	10 u	15.75 u
Change		- 6 u	+ 6 u
After	4 u	4 u	21.75 u

Number of chikoos to be transferred from Basket W to Basket X so that the number of chikoos in Basket V would be the same as Basket W.
= 10 u - 4 u
= 6 u
= 6 x 40
= 240

Answer(s): 240