There were some dragonfruits in 3 boxes, F, G and H. 20% of the number of dragonfruits in Box F was equal to 10% of the number of dragonfruits in Box G. The number of dragonfruits in Box H was 60% of the total number of dragonfruits. After Dylan removed 25% of the dragonfruits in Box H, there were 110 more dragonfruits in Box H than in Box G. In the end, how many dragonfruits should be transferred from Box G to Box H so that the number of dragonfruits in Box F would be the same as Box G?

Box F	Box G	Box H
1x2	2x2
2x3		3x3
2 u	4 u	9 u

	Box F	Box G	Box H
Before	2 u	4 u	9 u
Change			- 2.25 u
After	2 u	4 u	6.75 u

20% = ²⁰₁₀₀ = ¹₅

10% = ¹⁰₁₀₀ = ¹₁₀

¹₅ Box F = ¹₁₀ Box G

Box F : Box G
5 : 10
1 : 2

60% = ⁶⁰₁₀₀ = ³₅

The total number of dragonfruits in Box F and Box G is the combined repeated identity.  Make the total number of dragonfruits in Box F and Box G the same.  LCM of 3 and 2 = 6

Number of dragonfruits removed from Box H
= ²⁵₁₀₀ x 9 u
= 2.25 u

Number of dragonfruits left in Box H
= 9 u - 2.25 u
= 6.75 u

Number of more dragonfruits in Box H than Box G
= 6.75 u - 4 u
= 2.75 u

2.75 u = 110

1 u = 110 ÷ 2.75 = 40

	Box F	Box G	Box H
Before	2 u	4 u	6.75 u
Change		- 2 u	+ 2 u
After	2 u	2 u	8.75 u

Number of dragonfruits to be transferred from Box G to Box H so that the number of dragonfruits in Box F would be the same as Box G.
= 4 u - 2 u
= 2 u
= 2 x 40
= 80

Answer(s): 80