There were some pomegranates in 3 bags, F, G and H. 25% of the number of pomegranates in Bag F was equal to 10% of the number of pomegranates in Bag G. The number of pomegranates in Bag H was 60% of the total number of pomegranates. After Lee removed 25% of the pomegranates in Bag H, there were 230 more pomegranates in Bag H than in Bag G. In the end, how many pomegranates should be transferred from Bag G to Bag H so that the number of pomegranates in Bag F would be the same as Bag G?

Bag F	Bag G	Bag H
2x2	5x2
2x7		3x7
4 u	10 u	21 u

	Bag F	Bag G	Bag H
Before	4 u	10 u	21 u
Change			- 5.25 u
After	4 u	10 u	15.75 u

25% = ²⁵₁₀₀ = ¹₄

10% = ¹⁰₁₀₀ = ¹₁₀

¹₄ Bag F = ¹₁₀ Bag G

Bag F : Bag G
4 : 10
2 : 5

60% = ⁶⁰₁₀₀ = ³₅

The total number of pomegranates in Bag F and Bag G is the combined repeated identity.  Make the total number of pomegranates in Box F and Bag G the same.  LCM of 7 and 2 = 14

Number of pomegranates removed from Bag H
= ²⁵₁₀₀ x 21 u
= 5.25 u

Number of pomegranates left in Bag H
= 21 u - 5.25 u
= 15.75 u

Number of more pomegranates in Bag H than Bag G
= 15.75 u - 10 u
= 5.75 u

5.75 u = 230

1 u = 230 ÷ 5.75 = 40

	Bag F	Bag G	Bag H
Before	4 u	10 u	15.75 u
Change		- 6 u	+ 6 u
After	4 u	4 u	21.75 u

Number of pomegranates to be transferred from Bag G to Bag H so that the number of pomegranates in Bag F would be the same as Bag G.
= 10 u - 4 u
= 6 u
= 6 x 40
= 240

Answer(s): 240