There were some mangosteens in 3 boxes, K, L and M. 25% of the number of mangosteens in Box K was equal to 10% of the number of mangosteens in Box L. The number of mangosteens in Box M was 70% of the total number of mangosteens. After Harry removed 20% of the mangosteens in Box M, there were 242 more mangosteens in Box M than in Box L. In the end, how many mangosteens should be transferred from Box L to Box M so that the number of mangosteens in Box K would be the same as Box L?

Box K	Box L	Box M
2x3	5x3
3x7		7x7
6 u	15 u	49 u

	Box K	Box L	Box M
Before	6 u	15 u	49 u
Change			- 9.8 u
After	6 u	15 u	39.2 u

25% = ²⁵₁₀₀ = ¹₄

10% = ¹⁰₁₀₀ = ¹₁₀

¹₄ Box K = ¹₁₀ Box L

Box K : Box L
4 : 10
2 : 5

70% = ⁷⁰₁₀₀ = ⁷₁₀

The total number of mangosteens in Box K and Box L is the combined repeated identity.  Make the total number of mangosteens in Box K and Box L the same.  LCM of 7 and 3 = 21

Number of mangosteens removed from Box M
= ²⁰₁₀₀ x 49 u
= 9.8 u

Number of mangosteens left in Box M
= 49 u - 9.8 u
= 39.2 u

Number of more mangosteens in Box M than Box L
= 39.2 u - 15 u
= 24.2 u

24.2 u = 242

1 u = 242 ÷ 24.2 = 10

	Box K	Box L	Box M
Before	6 u	15 u	39.2 u
Change		- 9 u	+ 9 u
After	6 u	6 u	48.2 u

Number of mangosteens to be transferred from Box L to Box M so that the number of mangosteens in Box K would be the same as Box L.
= 15 u - 6 u
= 9 u
= 9 x 10
= 90

Answer(s): 90