There were some passion fruits in 3 boxes, L, M and N. 25% of the number of passion fruits in Box L was equal to 10% of the number of passion fruits in Box M. The number of passion fruits in Box N was 70% of the total number of passion fruits. After Jeremy removed 20% of the passion fruits in Box N, there were 968 more passion fruits in Box N than in Box M. In the end, how many passion fruits should be transferred from Box M to Box N so that the number of passion fruits in Box L would be the same as Box M?

Box L	Box M	Box N
2x3	5x3
3x7		7x7
6 u	15 u	49 u

	Box L	Box M	Box N
Before	6 u	15 u	49 u
Change			- 9.8 u
After	6 u	15 u	39.2 u

25% = ²⁵₁₀₀ = ¹₄

10% = ¹⁰₁₀₀ = ¹₁₀

¹₄ Box L = ¹₁₀ Box M

Box L : Box M
4 : 10
2 : 5

70% = ⁷⁰₁₀₀ = ⁷₁₀

The total number of passion fruits in Box L and Box M is the combined repeated identity.  Make the total number of passion fruits in Box L and Box M the same.  LCM of 7 and 3 = 21

Number of passion fruits removed from Box N
= ²⁰₁₀₀ x 49 u
= 9.8 u

Number of passion fruits left in Box N
= 49 u - 9.8 u
= 39.2 u

Number of more passion fruits in Box N than Box M
= 39.2 u - 15 u
= 24.2 u

24.2 u = 968

1 u = 968 ÷ 24.2 = 40

	Box L	Box M	Box N
Before	6 u	15 u	39.2 u
Change		- 9 u	+ 9 u
After	6 u	6 u	48.2 u

Number of passion fruits to be transferred from Box M to Box N so that the number of passion fruits in Box L would be the same as Box M.
= 15 u - 6 u
= 9 u
= 9 x 40
= 360

Answer(s): 360