There were some pomegranates in 3 bags, E, F and G. 25% of the number of pomegranates in Bag E was equal to 10% of the number of pomegranates in Bag F. The number of pomegranates in Bag G was 70% of the total number of pomegranates. After Julian removed 10% of the pomegranates in Bag G, there were 1455 more pomegranates in Bag G than in Bag F. In the end, how many pomegranates should be transferred from Bag F to Bag G so that the number of pomegranates in Bag E would be the same as Bag F?

Bag E	Bag F	Bag G
2x3	5x3
3x7		7x7
6 u	15 u	49 u

	Bag E	Bag F	Bag G
Before	6 u	15 u	49 u
Change			- 4.9 u
After	6 u	15 u	44.1 u

25% = ²⁵₁₀₀ = ¹₄

10% = ¹⁰₁₀₀ = ¹₁₀

¹₄ Bag E = ¹₁₀ Bag F

Bag E : Bag F
4 : 10
2 : 5

70% = ⁷⁰₁₀₀ = ⁷₁₀

The total number of pomegranates in Bag E and Bag F is the combined repeated identity.  Make the total number of pomegranates in Box E and Bag F the same.  LCM of 7 and 3 = 21

Number of pomegranates removed from Bag G
= ¹⁰₁₀₀ x 49 u
= 4.9 u

Number of pomegranates left in Bag G
= 49 u - 4.9 u
= 44.1 u

Number of more pomegranates in Bag G than Bag F
= 44.1 u - 15 u
= 29.1 u

29.1 u = 1455

1 u = 1455 ÷ 29.1 = 50

	Bag E	Bag F	Bag G
Before	6 u	15 u	44.1 u
Change		- 9 u	+ 9 u
After	6 u	6 u	53.1 u

Number of pomegranates to be transferred from Bag F to Bag G so that the number of pomegranates in Bag E would be the same as Bag F.
= 15 u - 6 u
= 9 u
= 9 x 50
= 450

Answer(s): 450