There were some passion fruits in 3 boxes, E, F and G. 25% of the number of passion fruits in Box E was equal to 10% of the number of passion fruits in Box F. The number of passion fruits in Box G was 60% of the total number of passion fruits. After Ian removed 20% of the passion fruits in Box G, there were 272 more passion fruits in Box G than in Box F. In the end, how many passion fruits should be transferred from Box F to Box G so that the number of passion fruits in Box E would be the same as Box F?

Box E	Box F	Box G
2x2	5x2
2x7		3x7
4 u	10 u	21 u

	Box E	Box F	Box G
Before	4 u	10 u	21 u
Change			- 4.2 u
After	4 u	10 u	16.8 u

25% = ²⁵₁₀₀ = ¹₄

10% = ¹⁰₁₀₀ = ¹₁₀

¹₄ Box E = ¹₁₀ Box F

Box E : Box F
4 : 10
2 : 5

60% = ⁶⁰₁₀₀ = ³₅

The total number of passion fruits in Box E and Box F is the combined repeated identity.  Make the total number of passion fruits in Box E and Box F the same.  LCM of 7 and 2 = 14

Number of passion fruits removed from Box G
= ²⁰₁₀₀ x 21 u
= 4.2 u

Number of passion fruits left in Box G
= 21 u - 4.2 u
= 16.8 u

Number of more passion fruits in Box G than Box F
= 16.8 u - 10 u
= 6.8 u

6.8 u = 272

1 u = 272 ÷ 6.8 = 40

	Box E	Box F	Box G
Before	4 u	10 u	16.8 u
Change		- 6 u	+ 6 u
After	4 u	4 u	22.8 u

Number of passion fruits to be transferred from Box F to Box G so that the number of passion fruits in Box E would be the same as Box F.
= 10 u - 4 u
= 6 u
= 6 x 40
= 240

Answer(s): 240