Tank R contained 4 times as many guppies as Tank S. When 10% of the guppies in Tank R and 20% of the guppies in Tank S were transferred to Tank T, Tank T had 72 guppies, which was 50% more guppies than before. How many less guppies were there in Tank S than Tank R in the end?
|
Tank R |
Tank S |
Tank T |
Before |
4 u |
1 u |
2x0.6 = 1.2 u |
Change |
- 0.4 u |
- 0.2 u |
+ 1x0.6 = + 0.6 u |
After |
3.6 u |
0.8 u |
3x0.6 = 1.8 u |
Number of guppies that were transferred from Tank R to Tank T
= 10% x 4 u
=
10100 x 4 u
= 0.4 u
Number of guppies that were transferred from Tank S to Tank T
= 20% x 1 u
=
20100 x 1 u
= 0.2 u
50% =
50100 =
12Some guppies from Tank R and Tank S were transferred to Tank T. The total number of guppies transferred from Tank R and Tank S into Tank T is the same.
Total number of guppies transferred from Tank R and Tank S into Tank T
= 0.4 u + 0.2 u
= 0.6 u
1.8 u = 72
1 u = 72 ÷ 1.8 = 40
Number of less guppies in Tank S than Tank R
= 3.6 u - 0.8 u
= 2.8 u
= 2.8 x 40
= 112
Answer(s): 112