Tank S contained 4 times as many guppies as Tank T. When 30% of the guppies in Tank S and 40% of the guppies in Tank T were transferred to Tank U, Tank U had 48 guppies, which was 50% more guppies than before. How many less guppies were there in Tank T than Tank S in the end?

	Tank S	Tank T	Tank U
Before	4 u	1 u	2x1.6 = 3.2 u
Change	- 1.2 u	- 0.4 u	+ 1x1.6 = + 1.6 u
After	2.8 u	0.6 u	3x1.6 = 4.8 u

Number of guppies that were transferred from Tank S to Tank U
= 30% x 4 u
= ³⁰₁₀₀ x 4 u
= 1.2 u

Number of guppies that were transferred from Tank T to Tank U
= 40% x 1 u
= ⁴⁰₁₀₀ x 1 u
= 0.4 u

50% = ⁵⁰₁₀₀ = ¹₂

Some guppies from Tank S and Tank T were transferred to Tank U.  The total number of guppies transferred from Tank S and Tank T into Tank U is the same.

Total number of guppies transferred from Tank S and Tank T into Tank U
= 1.2 u + 0.4 u
= 1.6 u

4.8 u = 48

1 u = 48 ÷ 4.8 = 10

Number of less guppies in Tank T than Tank S
= 2.8 u - 0.6 u
= 2.2 u
= 2.2 x 10
= 22

Answer(s): 22