Tank R contained 4 times as many guppies as Tank S. When 40% of the guppies in Tank R and 20% of the guppies in Tank S were transferred to Tank T, Tank T had 108 guppies, which was 20% more guppies than before. How many less guppies were there in Tank S than Tank R in the end?
|
Tank R |
Tank S |
Tank T |
Before |
4 u |
1 u |
5x1.8 = 9 u |
Change |
- 1.6 u |
- 0.2 u |
+ 1x1.8 = + 1.8 u |
After |
2.4 u |
0.8 u |
6x1.8 = 10.8 u |
Number of guppies that were transferred from Tank R to Tank T
= 40% x 4 u
=
40100 x 4 u
= 1.6 u
Number of guppies that were transferred from Tank S to Tank T
= 20% x 1 u
=
20100 x 1 u
= 0.2 u
20% =
20100 =
15Some guppies from Tank R and Tank S were transferred to Tank T. The total number of guppies transferred from Tank R and Tank S into Tank T is the same.
Total number of guppies transferred from Tank R and Tank S into Tank T
= 1.6 u + 0.2 u
= 1.8 u
10.8 u = 108
1 u = 108 ÷ 10.8 = 10
Number of less guppies in Tank S than Tank R
= 2.4 u - 0.8 u
= 1.6 u
= 1.6 x 10
= 16
Answer(s): 16