Tank M contained 2 times as many guppies as Tank N. When 20% of the guppies in Tank M and 40% of the guppies in Tank N were transferred to Tank P, Tank P had 48 guppies, which was 50% more guppies than before. How many more guppies were there in Tank P than Tank N in the end?
|
Tank M |
Tank N |
Tank P |
Before |
2 u |
1 u |
2x0.8 = 1.6 u |
Change |
- 0.4 u |
- 0.4 u |
+ 1x0.8 = + 0.8 u |
After |
1.6 u |
0.6 u |
3x0.8 = 2.4 u |
Number of guppies that were transferred from Tank M to Tank P
= 20% x 2 u
=
20100 x 2 u
= 0.4 u
Number of guppies that were transferred from Tank N to Tank P
= 40% x 1 u
=
40100 x 1 u
= 0.4 u
50% =
50100 =
12Some guppies from Tank M and Tank N were transferred to Tank P. The total number of guppies transferred from Tank M and Tank N into Tank P is the same.
Total number of guppies transferred from Tank M and Tank N into Tank P
= 0.4 u + 0.4 u
= 0.8 u
2.4 u = 48
1 u = 48 ÷ 2.4 = 20
Number of more guppies in Tank P than Tank N
= 2.4 u - 0.6 u
= 1.8 u
= 1.8 x 20
= 36
Answer(s): 36