Crate F contains 5 gold balls and 13 yellow balls. Crate G contains 53 gold balls and 17 yellow balls. How many yellow balls and gold balls must be removed from Crate G to put into Crate F so that 50% of the balls in Crate A are gold and 75% of the balls in Crate G are gold?

	Crate F		Crate G
	Gold balls	Yellow balls	Gold balls	Yellow balls
Before	5	13	53	17
Change	+ ?	+ ?	- ?	- ?
After	1 u	1 u	3 p	1 p

50% = ⁵⁰₁₀₀ = 12

75% = ⁷⁵₁₀₀ = 34

Number of gold balls = 5 + 53 = 58 

Number of yellow balls = 13 + 17 = 30 

1 u + 3 p = 58 --- (1)

1 u + 1 p = 30 ---(2)

(1) - (2)
(1 u + 3 p) - (1 u + 1 p) = 58 - 30
3 p - 1 p = 28
2 p = 28

1 p = 28 ÷ 2 = 14

From (2):
1 u + 1 p = 30
1 u + 1 x 14 = 30
1 u + 14 = 30

1 u = 30 - 14 = 16

Number of yellow balls to be removed from Crate G to Crate F
= 17 - 1 p
= 17 - 1 x 14
= 17 - 14
= 3

Number of gold balls to be removed from Crate G to Crate F
= 1 u - 5
= 16 - 5
= 11

Total number of yellow and gold balls to be removed from Crate G to Crate F
= 3 + 11
= 14

Answer(s): 14