Container G contains 17 yellow marbles and 9 black marbles. Container H contains 50 yellow marbles and 22 black marbles. How many black marbles and yellow marbles must be removed from Container H to put into Container G so that 50% of the marbles in Container A are yellow and 80% of the marbles in Container H are yellow?
|
Container G |
Container H |
|
Yellow marbles |
Black marbles |
Yellow marbles |
Black marbles |
Before |
17 |
9 |
50 |
22 |
Change |
+ ? |
+ ? |
- ? |
- ? |
After |
1 u |
1 u |
4 p |
1 p |
50% =
50100 = 12
80% =
80100 = 45
Number of yellow marbles = 17 + 50 = 67
Number of black marbles = 9 + 22 = 31
1 u + 4 p = 67 --- (1)
1 u + 1 p = 31 ---(2)
(1) - (2)
(1 u + 4 p) - (1 u + 1 p) = 67 - 31
4 p - 1 p = 36
3 p = 36
1 p = 36 ÷ 3 = 12
From (2):
1 u + 1 p = 31
1 u + 1 x 12 = 31
1 u + 12 = 31
1 u = 31 - 12 = 19
Number of black marbles to be removed from Container H to Container G
= 22 - 1 p
= 22 - 1 x 12
= 22 - 12
= 10
Number of yellow marbles to be removed from Container H to Container G
= 1 u - 17
= 19 - 17
= 2
Total number of black and yellow marbles to be removed from Container H to Container G
= 10 + 2
= 12
Answer(s): 12