Crate A contains 10 black marbles and 15 brown marbles. Crate B contains 21 black marbles and 8 brown marbles. How many brown marbles and black marbles must be moved from Crate B to put into Crate A so that 50% of the marbles in Crate A are black and 70% of the marbles in Crate B are black?
|
Crate A |
Crate B |
|
Black marbles |
Brown marbles |
Black marbles |
Brown marbles |
Before |
10 |
15 |
21 |
8 |
Change |
+ ? |
+ ? |
- ? |
- ? |
After |
1 u |
1 u |
7 p |
3 p |
50% =
50100 = 12
70% =
70100 = 710
Number of black marbles = 10 + 21 = 31
Number of brown marbles = 15 + 8 = 23
1 u + 7 p = 31 --- (1)
1 u + 3 p = 23 ---(2)
(1) - (2)
(1 u + 7 p) - (1 u + 3 p) = 31 - 23
7 p - 3 p = 8
4 p = 8
1 p = 8 ÷ 4 = 2
From (2):
1 u + 3 p = 23
1 u + 3 x 2 = 23
1 u + 6 = 23
1 u = 23 - 6 = 17
Number of brown marbles to be moved from Crate B to Crate A
= 8 - 3 p
= 8 - 3 x 2
= 8 - 6
= 2
Number of black marbles to be moved from Crate B to Crate A
= 1 u - 10
= 17 - 10
= 7
Total number of brown and black marbles to be moved from Crate B to Crate A
= 2 + 7
= 9
Answer(s): 9