Container Q contains 12 purple beads and 6 yellow beads. Container R contains 26 purple beads and 14 yellow beads. How many yellow beads and purple beads must be moved from Container R to put into Container Q so that 50% of the beads in Container A are purple and 80% of the beads in Container R are purple?
|
Container Q |
Container R |
|
Purple beads |
Yellow beads |
Purple beads |
Yellow beads |
Before |
12 |
6 |
26 |
14 |
Change |
+ ? |
+ ? |
- ? |
- ? |
After |
1 u |
1 u |
4 p |
1 p |
50% =
50100 = 12
80% =
80100 = 45
Number of purple beads = 12 + 26 = 38
Number of yellow beads = 6 + 14 = 20
1 u + 4 p = 38 --- (1)
1 u + 1 p = 20 ---(2)
(1) - (2)
(1 u + 4 p) - (1 u + 1 p) = 38 - 20
4 p - 1 p = 18
3 p = 18
1 p = 18 ÷ 3 = 6
From (2):
1 u + 1 p = 20
1 u + 1 x 6 = 20
1 u + 6 = 20
1 u = 20 - 6 = 14
Number of yellow beads to be moved from Container R to Container Q
= 14 - 1 p
= 14 - 1 x 6
= 14 - 6
= 8
Number of purple beads to be moved from Container R to Container Q
= 1 u - 12
= 14 - 12
= 2
Total number of yellow and purple beads to be moved from Container R to Container Q
= 8 + 2
= 10
Answer(s): 10