Container F contains 7 pink balls and 15 black balls. Container G contains 97 pink balls and 41 black balls. How many black balls and pink balls must be moved from Container G to put into Container F so that 50% of the balls in Container A are pink and 70% of the balls in Container G are pink?
|
Container F |
Container G |
|
Pink balls |
Black balls |
Pink balls |
Black balls |
Before |
7 |
15 |
97 |
41 |
Change |
+ ? |
+ ? |
- ? |
- ? |
After |
1 u |
1 u |
7 p |
3 p |
50% =
50100 = 12
70% =
70100 = 710
Number of pink balls = 7 + 97 = 104
Number of black balls = 15 + 41 = 56
1 u + 7 p = 104 --- (1)
1 u + 3 p = 56 ---(2)
(1) - (2)
(1 u + 7 p) - (1 u + 3 p) = 104 - 56
7 p - 3 p = 48
4 p = 48
1 p = 48 ÷ 4 = 12
From (2):
1 u + 3 p = 56
1 u + 3 x 12 = 56
1 u + 36 = 56
1 u = 56 - 36 = 20
Number of black balls to be moved from Container G to Container F
= 41 - 3 p
= 41 - 3 x 12
= 41 - 36
= 5
Number of pink balls to be moved from Container G to Container F
= 1 u - 7
= 20 - 7
= 13
Total number of black and pink balls to be moved from Container G to Container F
= 5 + 13
= 18
Answer(s): 18