Container T contains 10 purple beads and 12 gold beads. Container U contains 111 purple beads and 49 gold beads. How many gold beads and purple beads must be transferred from Container U to put into Container T so that 50% of the beads in Container A are purple and 70% of the beads in Container U are purple?
|
Container T |
Container U |
|
Purple beads |
Gold beads |
Purple beads |
Gold beads |
Before |
10 |
12 |
111 |
49 |
Change |
+ ? |
+ ? |
- ? |
- ? |
After |
1 u |
1 u |
7 p |
3 p |
50% =
50100 = 12
70% =
70100 = 710
Number of purple beads = 10 + 111 = 121
Number of gold beads = 12 + 49 = 61
1 u + 7 p = 121 --- (1)
1 u + 3 p = 61 ---(2)
(1) - (2)
(1 u + 7 p) - (1 u + 3 p) = 121 - 61
7 p - 3 p = 60
4 p = 60
1 p = 60 ÷ 4 = 15
From (2):
1 u + 3 p = 61
1 u + 3 x 15 = 61
1 u + 45 = 61
1 u = 61 - 45 = 16
Number of gold beads to be transferred from Container U to Container T
= 49 - 3 p
= 49 - 3 x 15
= 49 - 45
= 4
Number of purple beads to be transferred from Container U to Container T
= 1 u - 10
= 16 - 10
= 6
Total number of gold and purple beads to be transferred from Container U to Container T
= 4 + 6
= 10
Answer(s): 10