Container E contains 2 silver beads and 9 brown beads. Container F contains 56 silver beads and 23 brown beads. How many brown beads and silver beads must be transferred from Container F to put into Container E so that 50% of the beads in Container A are silver and 75% of the beads in Container F are silver?

	Container E		Container F
	Silver beads	Brown beads	Silver beads	Brown beads
Before	2	9	56	23
Change	+ ?	+ ?	- ?	- ?
After	1 u	1 u	3 p	1 p

50% = ⁵⁰₁₀₀ = 12

75% = ⁷⁵₁₀₀ = 34

Number of silver beads = 2 + 56 = 58 

Number of brown beads = 9 + 23 = 32 

1 u + 3 p = 58 --- (1)

1 u + 1 p = 32 ---(2)

(1) - (2)
(1 u + 3 p) - (1 u + 1 p) = 58 - 32
3 p - 1 p = 26
2 p = 26

1 p = 26 ÷ 2 = 13

From (2):
1 u + 1 p = 32
1 u + 1 x 13 = 32
1 u + 13 = 32

1 u = 32 - 13 = 19

Number of brown beads to be transferred from Container F to Container E
= 23 - 1 p
= 23 - 1 x 13
= 23 - 13
= 10

Number of silver beads to be transferred from Container F to Container E
= 1 u - 2
= 19 - 2
= 17

Total number of brown and silver beads to be transferred from Container F to Container E
= 10 + 17
= 27

Answer(s): 27